50=-16x^2+63x+4

Solution for 50=-16x^2+63x+4 equation:

50=-16x^2+63x+4

We move all terms to the left:

50-(-16x^2+63x+4)=0

We get rid of parentheses

16x^2-63x-4+50=0

We add all the numbers together, and all the variables

16x^2-63x+46=0

a = 16; b = -63; c = +46;
Δ = b2-4ac
Δ = -632-4·16·46
Δ = 1025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1025}=\sqrt{25*41}=\sqrt{25}*\sqrt{41}=5\sqrt{41}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-63)-5\sqrt{41}}{2*16}=\frac{63-5\sqrt{41}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-63)+5\sqrt{41}}{2*16}=\frac{63+5\sqrt{41}}{32}
$